4x^2+13x-17=0

Solution for 4x^2+13x-17=0 equation:

4x^2+13x-17=0

a = 4; b = 13; c = -17;
Δ = b2-4ac
Δ = 132-4·4·(-17)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-21}{2*4}=\frac{-34}{8}
=-4+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+21}{2*4}=\frac{8}{8}
=1
$